Question:medium

Polarizability of halide ions increases in the order:

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Polarizability increases with increasing size and number of electrons in an ion. For halide ions, the order of polarizability is \( \text{F}^-<\text{Cl}^-<\text{Br}^-<\text{I}^- \).
Updated On: Nov 26, 2025
  • \( \text{F}^-<\text{I}^-<\text{Br}^-<\text{Cl}^- \)
  • \( \text{Cl}^-<\text{Br}^-<\text{I}^-<\text{F}^- \)
  • \( \text{I}^-<\text{Br}^-<\text{Cl}^-<\text{F}^- \)
  • \( \text{F}^-<\text{Cl}^-<\text{Br}^-<\text{I}^- \)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding Polarizability
Polarizability describes an ion or atom's capacity for its electron cloud to be distorted by an external electric field. Generally, larger ions with more electrons exhibit higher polarizability.
Step 2: Analyzing Halide Ions

The halide ions are \( \text{F}^- \), \( \text{Cl}^- \), \( \text{Br}^- \), and \( \text{I}^- \). Their polarizability increases proportionally with their size and electron count.
Step 3: Order of Polarizability

The polarizability order for halide ions is as follows:\[\text{F}^-<\text{Cl}^-<\text{Br}^-<\text{I}^-.\]
This progression is due to \( \text{I}^- \) being the largest and possessing the most electrons, rendering it the most polarizable, while \( \text{F}^- \) is the smallest and least polarizable.
Step 4: Matching with the Options

The established order \( \text{F}^-<\text{Cl}^-<\text{Br}^-<\text{I}^- \) aligns with option (D).Final Answer: The polarizability of halide ions exhibits an increasing trend in the sequence \( \text{F}^-<\text{Cl}^-<\text{Br}^-<\text{I}^- \).
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