The problem involves calculating the percentage error in the estimation of kinetic energy when both mass and speed have measurement errors. Let's break down the solution step-by-step:
Step 1: Understanding Kinetic Energy Formula
The formula for kinetic energy (KE) is given as:
KE = \frac{1}{2} m v^2
where m is the mass and v is the speed of the object.
Step 2: Percentage Error in Variables
The percentage error in mass, \Delta m\% = 2\%, and the percentage error in speed, \Delta v\% = 3\%.
Step 3: Apply Error Propagation to Kinetic Energy
For a product of quantities, the relative error in the result is the sum of the relative errors in the quantities:
\frac{\Delta KE}{KE} = \frac{\Delta m}{m} + 2 \times \frac{\Delta v}{v}
Thus, the percentage error in kinetic energy is:
\Delta KE\% = \Delta m\% + 2 \times \Delta v\%
Step 4: Calculate the Total Percentage Error
Plug in the given percentage errors:
\Delta KE\% = 2\% + 2 \times 3\%
Simplifying this, we get:
\Delta KE\% = 2\% + 6\% = 8\%
Conclusion
The percentage error in the estimation of kinetic energy will be 8\%. This matches the correct answer choice given in the options.
Mass = \( (28 \pm 0.01) \, \text{g} \), Volume = \( (5 \pm 0.1) \, \text{cm}^3 \). What is the percentage error in density?