Ozone when reacts with potassium iodide solution liberates a substance which turns starch paper blue. The liberated substance is:

Question

Given below are two statements :
Statement I: The boiling point of hydrides of Group 16 elements follow the order
H₂O > H₂Te > H₂Se > H₂S.
Statement II: On the basis of molecular mass, H₂O is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H₂O, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below :

Answer 1

Step 1: Understanding the Concept:
Ozone (\( \text{O}_{3} \)) is a powerful oxidizing agent. It reacts with iodides to oxidize the iodide ion (\( \text{I}^{-} \)) to neutral iodine (\( \text{I}_{2} \)).
Step 2: Detailed Explanation:
When Ozone is passed through an aqueous solution of Potassium Iodide (\( \text{KI} \)), the following reaction occurs:
\[ 2\text{KI} + \text{H}_{2}\text{O} + \text{O}_{3} \longrightarrow 2\text{KOH} + \text{I}_{2} + \text{O}_{2} \]
In this reaction, the \( \text{I}^{-} \) ions are oxidized to elemental Iodine (\( \text{I}_{2} \)).
Iodine has a characteristic property of forming a deep blue-colored complex with starch.
Therefore, the liberation of iodine is confirmed by the blue color observed on starch paper.
Step 3: Final Answer:
The liberated substance is iodine.

Ozone when reacts with potassium iodide solution liberates a substance which turns starch paper blue. The liberated substance is:

Show Hint

The Correct Option is B

Solution and Explanation

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