Oxidation numbers of oxygen in H_2O_2 and H_2O:

Question

$\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:

Answer 1

Peroxides are a special case in oxidation-number rules: whenever two oxygen atoms are directly bonded to each other, as in hydrogen peroxide, each one is only assigned -1, not the usual -2. Water has no such oxygen-oxygen bond, so its single oxygen keeps the standard -2. That's why the pair of values is -1 and -2, option (A).

Oxidation numbers of oxygen in H_2O_2 and H_2O:

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The Correct Option is A

Solution and Explanation

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