Question:medium

One second after projection, the horizontal and vertical velocities of a projectile are found to be equal and after one more second, the motion of the projectile is along the horizontal. The horizontal range of the projectile is \[ (g=10~\text{m s}^{-2}) \]

Show Hint

Projectile formulas: \[ \boxed{ T=\frac{2u_y}{g}, \qquad R=u_xT } \] Horizontal motion has \[ \boxed{v_y=0.} \]
Updated On: Jul 15, 2026
  • \(10~\text{m}\)
  • \(20~\text{m}\)
  • \(30~\text{m}\)
  • \(40~\text{m}\)
Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?
0