Observe the following statements
Statement - I: The choice of reducing agent for the reduction of an oxide ore can be predicted by using Ellingham diagram, a plot of $\Delta G^\circ$ Vs T.
Statement - II: According to Ellingham diagram, metal oxide with higher $\Delta G^\circ$ is more stable than the oxide with lower $\Delta G^\circ$.
The correct answer is
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In an Ellingham diagram:
1. Lower line means more stable oxide.
2. A metal can reduce an oxide of another metal whose line lies above it at a given temperature.
3. The slope of the lines is related to the change in entropy ($\Delta S$) for the formation reaction. Most lines slope upwards because the reactions consume gas (O$_2$), decreasing entropy.