Question:medium

Observe the following set of reactions \[ Y \xrightarrow[\text{NaNH}_2(l)]{} \mathrm{C_2H_2} \xrightarrow[\mathrm{H_2}/\mathrm{Pt}]{} X \] Hybridization of carbon in \(X\) and \(Y\), respectively is

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Hybridization of carbon: \begin{itemize} \item Single bond \(\rightarrow sp^3\) \item Double bond \(\rightarrow sp^2\) \item Triple bond \(\rightarrow sp\) \end{itemize} Hydrogenation converts multiple bonds into single bonds, increasing the hybridization from \(sp\) to \(sp^3\).
Updated On: Jul 9, 2026
  • \(sp,\;sp^2\)
  • \(sp^3,\;sp^3\)
  • \(sp^2,\;sp^3\)
  • \(sp^3,\;sp\) \bigskip
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The Correct Option is D

Solution and Explanation

Step 1: X: hydrogenation of acetylene → ethane (C₂H₆), carbons sp³. Y: NaNH₂/NH₃(l) on vicinal dihalide → acetylene, carbons sp.

Step 2:
Write the final answer. \(\boxed{sp^3,\;sp}\)
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