Question:medium

Numerically greatest term in the expansion of $(3x-4y)^{23}$ when $x=\frac{1}{6}$ and $y=\frac{1}{8}$ is

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For $(a+b)^n$, the numerically greatest term occurs where $|\frac{T_{r+1}}{T_r}| \le 1$. If n is odd, the two middle terms have equal maximum magnitude.
Updated On: Mar 30, 2026
  • $\frac{^{23}C_{11}}{6^{23}}$
  • $^{23}C_{11} (\frac{8}{6})^{23}$
  • $^{23}C_{11} (\frac{6}{8})^{23}$
  • $^{23}C_{11}$
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The Correct Option is D

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