Comprehension

Nucleophiles attack at that part of the substrate molecule which is electron deficient. The reaction in which a nucleophile replaces an already existing nucleophile in a molecule is called a nucleophilic substitution reaction. Haloalkanes are substrates in these reactions. In this type of reaction, a nucleophile reacts with a haloalkane (the substrate) having a partial positive charge on the carbon atom bonded to halogen. A substitution reaction takes place, and the halogen atom, called the leaving group, departs as a halide ion. Since the substitution reaction is initiated by a nucleophile, it is called a nucleophilic substitution reaction.

\(Nu^− +C-X →C-Nu+X^−\)

Question: 1

When NaOH reacts with R-X, what is the major product?

Updated On: Mar 27, 2026
  • Alcohol
  • Ether
  • Ester
  • Acid
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The Correct Option is A

Solution and Explanation

When sodium hydroxide (NaOH) reacts with a haloalkane (R-X), the predominant product is an alcohol. This process exemplifies a nucleophilic substitution reaction.

Nucleophiles, such as the hydroxide ion (\(\text{OH}^-\)) derived from NaOH, target electron-deficient molecular sites. In this reaction, the haloalkane (R-X) functions as the substrate, where 'R' denotes an alkyl group and 'X' represents a halogen. Due to the halogen's higher electronegativity compared to carbon, the carbon atom develops a partial positive charge, rendering it vulnerable to nucleophilic assault.

The \(\text{OH}^-\) ion displaces the halogen atom because of its nucleophilic character, yielding an alcohol (\(R-\text{OH}\)) and liberating a halide ion as a byproduct.

Nu^-+C-X→C-Nu+X^−

In this formulation:

  • \(Nu^- = \text{OH}^-\) (The nucleophile from NaOH)
  • \(C-X = \text{RX}\) (The haloalkane substrate)
  • \(C-Nu = R-\text{OH}\) (The resulting alcohol)
  • \(X^- = \text{Halide ion}\) (The leaving group)

This reaction mechanism dictates that the nucleophile (hydroxide ion) substitutes the leaving group (halogen), culminating in alcohol formation and establishing it as the primary reaction product.

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Question: 2

When KCN reacts with R-X, what is the major product?

Updated On: Mar 27, 2026
  • Alcohol
  • Ether
  • Isonitrile
  • Nitrile
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The Correct Option is D

Solution and Explanation

A nucleophilic substitution occurs when KCN reacts with an alkyl halide (R-X). The cyanide ion (CN), acting as a nucleophile from KCN, targets the electron-deficient carbon atom in R-X. This carbon atom is bonded to a halogen (X), which is electron-withdrawing. The halogen is then substituted by the nucleophile, generating the target compound.

\(R-X+KCN→R-CN+KX\)

Key components of this reaction include:

  • The alkyl halide (R-X), where X represents the halogen acting as the leaving group.
  • Potassium cyanide (KCN), which serves as the source of the cyanide nucleophile (CN).
  • The formation of R-CN occurs when the CN ion attacks the carbon atom and displaces the halogen X.

Consequently, the primary product synthesized is a nitrile (R-CN).

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Question: 3

When AgCN reacts with R-X, what is the major product?

Updated On: Mar 27, 2026
  • Alcohol
  • Ether
  • Isonitrile
  • Nitrile
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The Correct Option is C

Solution and Explanation

In the reaction between AgCN and R-X, AgCN acts as a nucleophile. AgCN can potentially react through its carbon or nitrogen atom. However, due to its structure and silver's higher affinity for the nitrogen, the carbon atom predominantly acts as the nucleophile.

Here's why:

  • The nitrogen in AgCN is more associated with the silver ion (Ag+), making the carbon atom electron-rich and thus more nucleophilic.
  • The carbon atom of the CN group attacks the electron-deficient carbon of R-X, displacing the halogen (X).

This nucleophilic substitution reaction yields an isonitrile, where R is bonded to the isocyanide (CN) group.

The major product of the reaction between AgCN and R-X is isonitrile.

Nucleophilic substitution occurs when a nucleophile attacks a partially positively charged carbon atom:

\(R-X + AgCN → R-NC + AgX\)

R-NC represents an isonitrile. Therefore, the correct answer is isonitrile.

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Question: 4

When KNO$_2$ reacts with R-X, what is the major product?

Updated On: Mar 27, 2026
  • Alcohol
  • Nitroalkane
  • Isonitrile
  • Alkyl nitrite
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The Correct Option is D

Solution and Explanation

In this reaction, potassium nitrite (KNO2) provides the nucleophile, the nitrite ion (NO2-). R-X represents a haloalkane, where R is an alkyl group and X is a halogen. The carbon atom bonded to the halogen in a haloalkane carries a partial positive charge, making it susceptible to nucleophilic attack. The reaction proceeds via a nucleophilic substitution mechanism, where one nucleophile replaces another.

Nucleophilic substitution reactions generally follow the pattern:

\(Nu^− +C-X →C-Nu+X^−\)

In this specific reaction:

  • The nucleophile is NO2-.
  • The leaving group is the halide ion, X-.
  • The substrate is the haloalkane, R-X.

The NO2- ion, acting as the nucleophile, attacks the carbon atom bonded to the halogen (X). This results in the displacement of the halide ion and the formation of an alkyl nitrite as the primary product.

ReactantsProduct
R-X + KNO2R-O-N=O

Therefore, the reaction of KNO2 with R-X predominantly yields alkyl nitrite, R-O-N=O. This synthesis exemplifies a standard nucleophilic substitution mechanism, with the nitrite ion functioning as the nucleophile to produce an alkyl nitrite.

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Question: 5

When NH3 reacts with R-X, what is the major product?

Updated On: Jan 16, 2026
  • Nitroalkane
  • Isonitrile
  • Alkyl nitrite
  • Primary amine
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The Correct Option is D

Solution and Explanation

Nucleophilic substitution reactions are fundamental in organic chemistry. In these reactions, an electron-rich nucleophile attacks an electron-deficient carbon atom, typically in haloalkanes (R-X). The halogen (X) functions as the leaving group, being displaced by the nucleophile.

An illustration of this is the reaction between ammonia (NH3) and a haloalkane (R-X). Ammonia, acting as the nucleophile, attacks the carbon atom. The process involves the nucleophile (NH3) substituting the leaving group (X) on the substrate (R-X).

The general reaction mechanism is:

\(NH_3 + R-X \rightarrow R-NH_3^+ + X^-\)

The initial product formed is an alkylammonium ion (R-NH3+). Subsequent deprotonation of this ion yields a primary amine (R-NH2).

\(R-NH_3^+ + OH^- \rightarrow R-NH_2 + H_2O\)

Consequently, the primary product of the reaction between NH3 and R-X is a primary amine. This outcome is due to the efficiency of the nucleophilic substitution in replacing the halide ion with the amine group.

ReactantMajor Product
NH3 + R-XPrimary Amine (R-NH2)
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