Question:medium

Neha appeared for her judiciary preliminary examination on 12th November 2009, which was a Thursday. On which of the following dates did 12th November again fall on a Thursday?

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The day of the week repeats when the sum of odd days becomes a multiple of 7. For non-leap years, the calendar usually repeats after 6 or 11 years.
Updated On: Jun 30, 2026
  • 12th November 2014
  • 12th November 2015
  • 12th November 2016
  • 12th November 2017
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The Correct Option is B

Solution and Explanation

Step 1: Recall the odd days method.
An ordinary year contributes 1 odd day; a leap year contributes 2 odd days; for 12 Nov to fall on Thursday again, the total accumulated odd days from 2009 must be a multiple of 7.
Step 2: Accumulate odd days year by year.
2010 (ordinary) = 1; 2011 = 1; 2012 (leap) = 2; 2013 = 1; 2014 = 1; 2015 = 1; running total = $1+1+2+1+1+1 = 7$ odd days by 12 Nov 2015.
Step 3: Confirm the target year.
$7 \mod 7 = 0$, so 12 Nov 2015 falls on the same weekday as 12 Nov 2009, which is Thursday.
\[ \boxed{2015} \]
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