Question

Mr. Kapoor has Bb autosomal gene pair and d allele sex-linked. What shall be proportion of Bd in sperms

• A. zero
• B. 44563
• C. 44565
• D. 1/8.

Answer 1

The Correct Option is C

To determine the proportion of Bd in sperms, we need to analyze the genetic makeup. Mr. Kapoor has the genetic configuration involving an autosomal gene pair Bb and a sex-linked allele d. Let's break this down step-by-step: 

Step 1: Analyze Autosomal Gene Pair (Bb)

The genotype Bb means Mr. Kapoor is heterozygous for this gene. When forming gametes (sperms), each allele of the gene pair segregates independently. Therefore, there is an equal probability of the sperm carrying either B or b. So, the probability for each is:

\(\frac{1}{2}\) for B and \(\frac{1}{2}\) for b.

Step 2: Analyze Sex-linked Allele (d)

The problem states that d is a sex-linked allele. Assuming it is located on the X chromosome (as is typical for sex-linked genes), the gametes will carry this sex chromosome. For males with normal sex chromosome configuration XY, when forming sperms, the probability of carrying the X chromosome (and thus the d allele) is:

\(\frac{1}{2}\). The other half carries the Y chromosome with no d allele.

Step 3: Calculate Probability for Combination Bd

To calculate the probability of a sperm having the combination Bd, multiply the individual probabilities:

\(\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\).

Considering the options given, the correct choice is

44565

. It seems there might be a typographical error in the options as the logic clearly shows the proportion of Bd in the sperm should be \(\frac{1}{4}\).

 

Conclusion: The correct answer based on logical understanding and probability calculation should be \(\frac{1}{4}\) for Bd in the sperms if correctly presented. Please consider checking the provided options for errors.