Step 1: Build a general formula instead of solving one case at a time.
If a clock takes $T$ seconds to strike $n$ gongs, the time per gap is $\frac{T}{n-1}$, since $n$ gongs create only $n-1$ waiting gaps.
Step 2: Plug in the seven o'clock case to find the gap time.
Here $n=7$ and $T=7$, so gap time = $\frac{7}{7-1} = \frac{7}{6}$ seconds. This gap time is a fixed property of the clock, it stays the same no matter what hour it strikes.
Step 3: Use the formula again for eleven o'clock.
For eleven o'clock, $n=11$, so the number of gaps is $11-1=10$. Total time = $10 \times \frac{7}{6} = \frac{70}{6}$ seconds.
Step 4: Convert to decimal.
$\frac{70}{6} = 11.6666...$ seconds, which rounds to 11.66666667 seconds as given in the options.
Final Answer:
The clock takes $\frac{70}{6}$ seconds, about 11.67 seconds, to strike eleven o'clock.
\[ \boxed{11.67 \text{ seconds}} \]