Question:medium

Mean deviation from the mean for the ungrouped data \[ 8,\,7,\,15,\,12,\,12,\,60,\,15,\,6,\,65,\,4,\,6,\,18 \] is

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For ungrouped data: \[ \text{Mean Deviation about Mean} = \frac{\sum |x-\bar x|}{n}. \] Always take absolute values before adding deviations; otherwise positive and negative deviations cancel out.
Updated On: Jun 17, 2026
  • \(14.5\)
  • \(11.16\)
  • \(12.6\)
  • \(13.4\)
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The Correct Option is A

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