Question:medium

Mean and variance of an ungrouped data of 15 numbers are \(12\) and \(14\) respectively. For another ungrouped data of 15 numbers the mean and variance are \(14\) and \(10\) respectively. If the two data are combined, then the variance of the combined data of 30 numbers is

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For combining two data sets, \[ \boxed{ \sigma^2 = \frac{ n_1(\sigma_1^2+d_1^2) + n_2(\sigma_2^2+d_2^2) } {n_1+n_2}, } \] where \[ d_i=\bar{x}_i-\bar{x}. \]
Updated On: Jul 18, 2026
  • \(12\)
  • \(16\)
  • \(13\)
  • \(15\)
Show Solution

The Correct Option is C

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