Question

Match the Xenon compounds in Column-I with its structure in Column II and assign the correct code:

Column I		Column II
A	\(XeF_4\)	I	pyramidall
B	\(XeFe_6 \)	II	square planar
C	\(XeOF_4  \)	III	distorted octahedral
D	\(XeO_3\)	IV	square pyramidal

Code:

• A. (a)-(i) (b)-(ii) (c)-(iii) (d)-(iv)
• B. (a)-(ii) (b)-(iii) (c)-(iv) (d)-(i)
• C. (a)-(ii) (b)-(iii) (c)-(i) (d)-(iv)
• D. (a)-(iii) (b)-(iv) (c)-(i) (d)-(ii)

Answer 1

The Correct Option is B

To solve the given problem, we need to match the Xenon compounds listed in Column I with their corresponding structures in Column II. Let's analyze each compound one by one:

1. XeF_4: Xenon tetrafluoride has a square planar geometry. This occurs because Xenon has eight valence electrons, and the bonding involves four fluorine atoms, leading to a symmetrical structure with lone pairs filling the equatorial positions to minimize electron repulsion. Thus, it matches with II.
2. XeFe_6: This is an incorrect representation, as the correct compound should be XeF_6, which has a distorted octahedral shape due to lone pair-bond pair repulsion. Thus, it matches with III.
3. XeOF_4: This compound is square pyramidal because Xenon forms bonds with four fluorines and one oxygen, while the lone pair induces the pyramidal geometry. Thus, it matches with IV.
4. XeO_3: Xenon trioxide is pyramidal rather than a planar structure due to the presence of lone pairs creating a trigonal pyramidal geometry. Thus, it matches with I.

Therefore, the correct matching will be:

1. (A) XeF_4 - (II) square planar
2. (B) XeF_6 - (III) distorted octahedral
3. (C) XeOF_4 - (IV) square pyramidal
4. (D) XeO_3 - (I) pyramidal

Based on the above reasoning, the correct code that matches the correct answers is (a)-(ii) (b)-(iii) (c)-(iv) (d)-(i).