Question:medium

Match the LIST-I with LIST-II 

Choose the correct answer from the options given below:

Show Hint

- Carbocation: \(\text{sp}^2\), 6 electrons, planar - Free radical: 7 electrons, can be \(\text{sp}^2\) or \(\text{sp}^3\) - Nucleophile: "nucleus loving" (e\(^-\) donor) - Electrophile: "electron loving" (e\(^-\) acceptor)
Updated On: Jan 14, 2026
  • A-III, B-III, C-I, D-IV
  • A-III, B-IV, C-II, D-I
  • A-IV, B-II, C-III, D-I
  • A-III, B-IV, C-I, D-II
Show Solution

The Correct Option is D

Solution and Explanation

To establish the correspondence between LIST-I and LIST-II, the definitions and attributes of each term must be understood:

  1. Carbocation: A carbocation features a carbon atom bearing a positive charge. It possesses an vacant p-orbital, rendering it electron-deficient. Therefore, a carbocation aligns with III (a sp2 hybridized carbon atom with an unoccupied p-orbital).
  2. Carbon Free Radical: A carbon free radical is characterized by a single unpaired electron, contributing to its reactivity. Consequently, it corresponds to IV (a sp2/sp3 hybridized carbon atom with one unpaired electron).
  3. Nucleophile: A nucleophile is defined as a species capable of donating an electron pair. Thus, it matches I (a species that can provide an electron pair).
  4. Electrophile: An electrophile is an electron-deficient species that can accept an electron pair. Hence, it corresponds to II (a species that can accept an electron pair).

Following the aforementioned analysis, the accurate matching is:

  • A - III
  • B - IV
  • C - I
  • D - II

Consequently, the correct selection is A-III, B-IV, C-I, D-II.

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