Question:medium

Match the LIST-I (Element) with LIST-II (Group)
\begin{tabular}{ll} LIST-I & LIST-II
A. O\(_2\) & I. Transitional metals
B. Po & II. Non-metal
C. Os & III. Metalloid
D. Se & IV. Noble gas
\end{tabular}

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When classifying elements, remember the main blocks of the periodic table: metals on the left and center (including transition metals), a staircase of metalloids in the middle, non-metals on the right, and the noble gases in the far-right column.
Updated On: Feb 18, 2026
  • A - I, B - II, C - III, D - IV
  • A - IV, B - III, C - II, D - I
  • A - IV, B - III, C - I, D - II
  • A - III, B - IV, C - I, D - II
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The Correct Option is C

Solution and Explanation

Note: A typo exists in List-I; \(\text{O}_2\) should be a noble gas (e.g., Xenon, Xe; or Neon, Ne) for classification. Assume A = Xe.
Step 1: Element Classification
A. Xe: Xenon is a noble gas; thus, A matches IV.
B. Po: Polonium, a metalloid, has intermediate metal/non-metal properties; thus, B matches III.
C. Os: Osmium is a dense, hard, brittle, bluish-white transition metal; thus, C matches I.
D. Se: Selenium is a non-metal; thus, D matches II.
Conclusion: The result is A-IV, B-III, C-I, D-II, corresponding to option (3).
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