Question:easy

Match List-I with List-II
List-IList-II
(A) pip install pandas(I) one-dimensional array containing a sequence of values
(B) Numpy array(II) can have different data types
(C) Pandas DataFrame(III) requires homogeneous data
(D) Series(IV) install Pandas library
Choose the correct answer from the options given below:

Show Hint

pip install installs a library. NumPy arrays are homogeneous. DataFrame columns can differ in type. Series is one-dimensional.
Updated On: Oct 1, 2026
  • (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
  • (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  • (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
  • (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Idea:
We can solve this by anchoring on the pairs we are most sure about, then removing options that disagree. The two surest facts are what the install command does and what a Series is.

Step 2: Anchor pairs.
Only one line in List-II talks about installing, which is (IV). Only the command pip install pandas can go with it. So (A) is paired with (IV).
Only one line in List-II describes a one-dimensional array of a sequence of values, which is (I). That is the definition of a Series. So (D) is paired with (I).

Step 3: Eliminate options.
Option 2 has (A)-(I), which breaks the first anchor. Option 3 also has (A)-(I). Option 4 has (A)-(III) and (D)-(II), which break both anchors. Only option 1 keeps (A)-(IV) and (D)-(I).

Step 4: Confirm the remaining pairs.
Option 1 says (B)-(III) and (C)-(II). A NumPy array needs all items of the same type, so it is homogeneous (III). A DataFrame can mix data types across columns (II). Both agree with what we know.

Step 5: Extra check.
Let us also test the option pairs another way. In every wrong option, at least one pair is clearly false. For example, a DataFrame is never limited to one data type, so any option that pairs (C) with (III) is wrong. In the same way, a NumPy array is never described as installing a library, so any option that pairs (B) with (IV) is wrong. Doing these two quick tests alone removes options 2, 3 and 4, and leaves only option 1.

Step 6: Conclusion.
Option 1 is the only consistent choice. \[ \boxed{(A)-(IV),\ (B)-(III),\ (C)-(II),\ (D)-(I)} \]
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