Question

Given the following series ser1:

Index	Value
0	69
1	80
2	20
3	50
4	100
5	70

State the output of the following command:

print(ser1 >= 70)

• A.

  Index	Value
  1	80
  4	100
  5	70

• B.

  Index	Result
  0	F
  1	T
  2	F
  3	F
  4	T
  5	T

• C.

  Index	Condition
  1	T
  4	T
  5	T

• D.

  Index	Value
  1	80
  4	100

Hint:

Remember: Relational operations on Pandas Series return Boolean Series. To filter values, use Boolean indexing like ser1[ser1 >= 70].

Answer 1

The Correct Option is B

Step 1: Recall comparison operation on Pandas Series.
When a relational operator (like >=) is applied on a Series, the output is a Boolean Series of the same size, where each element is True (T) or False (F) depending on the condition.
Step 2: Apply condition ser1 >= 70
- Index 0 → 69 >= 70? → False (F)
- Index 1 → 80 >= 70? → True (T)
- Index 2 → 20 >= 70? → False (F)
- Index 3 → 50 >= 70? → False (F)
- Index 4 → 100 >= 70? → True (T)
- Index 5 → 70 >= 70? → True (T)

Step 3: Construct Boolean Series.
The result is: \[\begin{tabular}{|c|c|}\hline0 & F
1 & T
2 & F
3 & F
4 & T
5 & T
\hline\end{tabular}\]
Final Answer: \[\boxed{\text{Option (2)}}\]