Question

Match List I with List II

List I (Buffers)	List II (Applications)
(A) \(\text{HCO}_3^{-1}+\text{H}_2\text{CO}_3\)	(I) Maintain the pH of blood forms \(7.36\) to \(7.42\)
(B) Phosphates	(II) In Medicine
(C) Sodium Citrate	(III) In Qualitative analysis of basic radicals
(D) \(\text{NH}_4\text{Cl}+\text{NH}_4\text{OH}\)	(IV) In fertilizers

Choose the correct answer from the options given below:

• (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
• (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
• (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Hint:

Blood uses the bicarbonate buffer, and group analysis of basic radicals uses the ammonium buffer.

Answer 1

The Correct Option is C

Step 1: Approach:
Start with the two matches that are certain, then fill the rest by elimination.

Step 2: Certain matches:
The carbonic acid and bicarbonate pair is the blood buffer, so (A) goes with (I). This rules out options B and D, which pair (A) with something else.
The ammonium chloride and ammonia pair is used in qualitative analysis of basic radicals, so (D) goes with (III). Option A pairs (D) with (IV), so it fails and only option C remains.

Step 3: Remaining pairs:
Phosphates then go with fertilizers (IV) and sodium citrate with medicine (II). These agree with option C, so we have a full match with no clash.

Final Answer:
The correct matching is (A)-(I), (B)-(IV), (C)-(II), (D)-(III), which is option (C). \[ \boxed{(A)\text{-}(I),\ (B)\text{-}(IV),\ (C)\text{-}(II),\ (D)\text{-}(III)} \]