Question:medium

Match List-I with List-II :  
List - IMoleculeList - IIBond enthalpy (kJ mol-1)
(A) HCl(I) 435.8
(B) N2(II) 498
(C) H2(III) 946.0
(D) O2 (IV) 431.0
Identify the correct answer from the options given below :

Updated On: Nov 26, 2025
  • A-III, B-IV, C-I, D-II
  • A-IV, B-I, C-III, D-II
  • A-IV, B-III, C-II, D-I
  • A-IV, B-III, C-I, D-II
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The Correct Option is D

Solution and Explanation

Bond enthalpy is defined as the energy needed to break one mole of a specific bond in a gaseous compound.
A. HCl: The H-Cl bond enthalpy is approximately 431 kJ mol$^{-1}$. This value is slightly lower than HBr but higher than HF, reflecting periodic trends within the halogen group. Therefore, A corresponds to IV.
B. N$_2$: The N≡N triple bond is exceptionally strong, possessing a bond enthalpy of approximately 946 kJ mol$^{-1}$. Thus, B matches with III.
C. H$_2$: The H-H single bond has a bond enthalpy of approximately 436 kJ mol$^{-1}$. Consequently, C is paired with I.
D. O$_2$: The O=O double bond exhibits a bond enthalpy of approximately 498 kJ mol$^{-1}$. Therefore, D is associated with II.
The resulting correct matching is A-IV, B-III, C-I, D-II.

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