Question

Match List - I with List- II.

	List-I (Products formed)		List-II (Reaction of carbonyl compound with)
(a)	Cyaniohydrin	(i)	NH2OH
(b)	Acetal	(ii)	RNH2
(c)	Schiff’s base	(iii)	alcohol
(d)	Oxime	(iv)	HCN

Choose the correct answer from the options given below:

• A. (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
• B. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
• C. (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
• D. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

Answer 1

The Correct Option is D

Step 1: Understanding the Concept:
Aldehydes and ketones react with various nucleophiles to form characteristic addition products.
The nature of the substituent on the nitrogen or oxygen nucleophile determines the final product name.
Detailed Explanation:
(a) Cyanohydrin: These are formed by the nucleophilic addition of hydrogen cyanide ($HCN$) to the carbonyl group.
The $CN^{-}$ ion attacks the carbon, followed by protonation of the oxygen.
Matching: (a) $\rightarrow$ (iv).
(b) Acetal: Aldehydes react with two equivalents of monohydric alcohols in the presence of dry $HCl$ gas to form acetals.
The reaction proceeds through a hemiacetal intermediate.
Matching: (b) $\rightarrow$ (iii).
(c) Schiff's base: Primary amines ($RNH_{2}$) react with carbonyl compounds to produce substituted imines, known as Schiff's bases.
The reaction involves addition followed by the elimination of a water molecule.
Matching: (c) $\rightarrow$ (ii).
(d) Oxime: Carbonyl compounds react with hydroxylamine ($NH_{2}OH$) to form oximes ($>C=N-OH$).
Matching: (d) $\rightarrow$ (i).
Step 2: Final Answer:
By aligning the pairs: (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i).
This corresponds to option (1).