Question

Match List-I with List – II :

	List-I (Oxoacids of Sulphur)		List-II (Bonds)
A	Peroxodisulphuric acid	I	Two S–OH, Four S=O, One S–O–S
B	Sulphuric acid	II	Two S–OH, One S=O
C	Pyrosulphuric acid	III	Two S–OH, Four S=O, One S–O–O–S
D	Sulphurous acid	IV	Two S–OH, Two S=O

Choose the correct answer from the options given below.

• A. A–III, B–IV, C–I, D–II
• B. A–I, B–III, C–IV, D–II
• C. A–I, B–III, C–IV, D–II
• D. A–I, B–III, C–II, D–IV

Answer 1

The Correct Option is A

To solve this question, we need to match the oxoacids of sulfur in List-I with their corresponding bond structures in List-II.

Let's analyze each compound:

1. Peroxodisulphuric acid (H₂S₂O₈): Also known as Marshall's acid. It has the following bond structure: Two S–OH groups, Four S=O double bonds, and One S–O–O–S bridge. This structure is represented by option III in List-II.
2. Sulphuric acid (H₂SO₄): Its structure contains Two S–OH groups and Two S=O double bonds. Therefore, it matches with option IV.
3. Pyrosulphuric acid (H₂S₂O₇): This compound has Two S–OH groups, Four S=O double bonds, and One S–O–S bond, corresponding with option I.
4. Sulphurous acid (H₂SO₃): The structure involves Two S–OH groups and One S=O double bond. It fits option II.

Based on the analysis above, the correct match is:

• A–III: Peroxodisulphuric acid with Two S–OH, Four S=O, One S–O–O–S.
• B–IV: Sulphuric acid with Two S–OH, Two S=O.
• C–I: Pyrosulphuric acid with Two S–OH, Four S=O, One S–O–S.
• D–II: Sulphurous acid with Two S–OH, One S=O.

The correct option is A–III, B–IV, C–I, D–II.