Question

Match List-I with List-Il:

	List-I		List-II
A.	Coke	I.	Carbon atoms are sp3 hybridized.
B.	Diamond	II.	Used as a dry lubricant.
C.	Fullerene	III.	Used as a reducing agent.
D.	Graphite	IV.	Cage like molecules

Choose the correct answer from the options given below:

• A. A-lV, B-I, C-II, D-III
• B. A-III, B-I, C-IV, D-II
• C. A-llI, B-IV, C-I, D-II
• D. A-II, B-IV, C-I, D-III

Answer 1

The Correct Option is B

To solve the given question, we must correctly match the substances in List-I with their properties in List-II. Let's break down the characteristics of each substance: 

1. Coke: Coke is a form of carbon and is commonly used as a reducing agent in metallurgical processes. It helps in the reduction of metal oxides to metals.
2. Diamond: In diamond, carbon atoms are sp³ hybridized, forming a rigid three-dimensional tetrahedral structure. This accounts for its hardness and high melting point.
3. Fullerene: Fullerenes are molecules made entirely of carbon, taking the form of a hollow sphere, ellipsoid, or tube. They are known for their cage-like structures, similar to Buckminsterfullerene (C₆₀), which resemble a soccer ball.
4. Graphite: Graphite is structured in layers where the carbon atoms are bonded in sheets of hexagons with sp² hybridization. The layers can easily slide over each other, making graphite an excellent lubricant.

Based on the explanations above, we can match List-I with List-II as follows:

A.	Coke	III.	Used as a reducing agent.
B.	Diamond	I.	Carbon atoms are sp3 hybridized.
C.	Fullerene	IV.	Cage like molecules
D.	Graphite	II.	Used as a dry lubricant.

Thus, the correct matching of List-I with List-II is:

• A-III: Coke is used as a reducing agent.
• B-I: Diamond has carbon atoms that are sp³ hybridized.
• C-IV: Fullerene has a cage-like molecular structure.
• D-II: Graphite is used as a dry lubricant.

Therefore, the correct answer is: A-III, B-I, C-IV, D-II.