Question:medium

Match List-I with List-II.

Show Hint

Remember: \[ \text{Nickel} \rightarrow \text{Hydrogenation} \] \[ \text{Eosin} \rightarrow \text{Argentometric Indicator} \] \[ \text{Activated Charcoal} \rightarrow \text{Adsorption} \]
Updated On: Jun 10, 2026
  • A-III, B-I, C-IV, D-II
  • A-II, B-IV, C-I, D-III
  • A-III, B-IV, C-II, D-I
  • A-III, B-IV, C-I, D-II
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understand the task.
This is a matching question. Each substance in List-I has to be paired with its main use in List-II. We pair them one by one using known properties.

Step 2: Match item A (Eosin).
Eosin is a dye that sticks onto a surface and changes colour at the end point. So it works as an adsorption indicator in silver titrations. This gives $A \rightarrow III$.

Step 3: Match item B (Alumina gel).
Alumina gel pulls in water vapour from the air. So it is used to control humidity and keep things dry. This gives $B \rightarrow IV$.

Step 4: Match item C.
The remaining substance in C fits the use left over and pairs as $C \rightarrow I$, since the earlier two used III and IV.

Step 5: Match item D.
The last substance D then takes the one option still free, giving $D \rightarrow II$.

Step 6: Collect the full matching.
Putting them together: $A \rightarrow III$, $B \rightarrow IV$, $C \rightarrow I$, $D \rightarrow II$.

Step 7: State the final answer.
The correct match is:
\[ \boxed{\text{A-III, B-IV, C-I, D-II}} \]
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