Question:medium

$\lim_{x \to 0} \frac{\sqrt[3]{\cos x} - \sqrt{\cos x}}{\sin^2 x} =$

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For limits involving trigonometric functions as $x \to 0$, using standard approximations like $\sin x \approx x$, $\cos x \approx 1 - x^2/2$, and the binomial approximation $(1+u)^n \approx 1+nu$ is often faster and less error-prone than repeated applications of L'Hopital's Rule.
Updated On: Mar 30, 2026
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Show Solution

The Correct Option is B

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