Question:medium

Let \( z=x+iy \) and \( P(x,y) \) be a point on the Argand plane. If \( z \) satisfies the condition \( \text{Arg}\left(\frac{z-3i}{z+2i}\right) = \frac{\pi}{4} \), then the locus of P is

Show Hint

For locus problems involving \( \text{Arg}((z-z_1)/(z-z_2)) = \theta \), the curve is a circle passing through \( z_1 \) and \( z_2 \). You can often eliminate options by simply checking if the coordinates of \( z_1 \) and \( z_2 \) satisfy the given equations.
Updated On: Mar 30, 2026
  • \( x^2+y^2-y-6=0, (x,y) \neq (0,-2) \)
  • \( x^2+y^2-x-y-6=0, (x,y) \neq (0,-2) \)
  • \( x^2+y^2+5x-y-6=0, (x,y) \neq (0,-2) \)
  • \( x^2+y^2+x-y-6=0, (x,y) \neq (0,-2) \)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The equation \( \text{Arg}\left(\frac{z-z_1}{z-z_2}\right) = \alpha \) represents an arc of a circle passing through \( z_1 \) and \( z_2 \). Here \( z_1 = 3i \) and \( z_2 = -2i \).
Step 2: Key Formula or Approach:
The points \( A(0,3) \) and \( B(0,-2) \) lie on the locus. We can check which option satisfies these points.
Substitute \( (0,3) \): \( 0+9+0-3-6 = 0 \). (Satisfied)
Substitute \( (0,-2) \): \( 0+4+0-(-2)-6 = 0 \). (Satisfied)
All options might satisfy this, so we need the full equation.
Since the angle is \( \pi/4 \), the center \( (h,k) \) forms a right angle with the chord \( AB \) at the center.
Step 3: Detailed Explanation:
The chord length \( AB = |3i - (-2i)| = 5 \). If \( R \) is the radius, \( R^2 + R^2 = AB^2 \implies 2R^2 = 25 \implies R^2 = 12.5 \). The perpendicular bisector of \( AB \) is \( y = \frac{3+(-2)}{2} = 0.5 \). So \( k = 0.5 \).
The distance from center to A is \( R \):
\( h^2 + (3-0.5)^2 = 12.5 \implies h^2 + 6.25 = 12.5 \implies h^2 = 6.25 \implies h = \pm 2.5 \).
The equation is \( (x-h)^2 + (y-0.5)^2 = 12.5 \).
\( x^2 - 2hx + h^2 + y^2 - y + 0.25 = 12.5 \)
\( x^2 + y^2 - 2hx - y + 6.5 = 12.5 \)
\( x^2 + y^2 - 2hx - y - 6 = 0 \).
We need to determine the sign of \( -2h \).
For \( \text{Arg} = \pi/4 \textgreater 0 \), the locus is on one side of the chord. Using the standard orientation or checking a point, the coefficient of \( x \) is \( +5 \).
Thus, the equation is \( x^2+y^2+5x-y-6=0 \).
Step 4: Final Answer:
The locus is \( x^2+y^2+5x-y-6=0 \).
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