Question:medium

Let Z be the ring of integers and $f: Z \to 2Z$ defined by $f(n)=2n$, $\forall n \in Z$. Then f is

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While $f(n)=2n$ is a group homomorphism for addition, the multiplier "2" breaks the multiplication requirement for rings.

Updated On: Jul 3, 2026

a ring homomorphism
not a ring homomorphism
a zero homomorphism
identity homomorphism

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The Correct Option is B

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