To solve the problem, we need to find the radius of circle \( C \) given two conditions: the lines \( (2 - i)z = (2 + i)\bar{z} \) and \( (2 + i)z + (i - 2)\bar{z} - 4i = 0 \) are normal to circle \( C \), and the line \( iz + \bar{z} + 1 + i = 0 \) is tangent to it.
Therefore, the radius of the circle \( C \) is \frac{3}{2\sqrt{2}}.



