To determine the value of α for which the vectors {[2, -3, α], [3, -1, 3], [1, -5, 7]} do not form a basis of R3, we need to check when they become linearly dependent. A set of vectors is linearly dependent if the determinant of the matrix formed by these vectors as rows (or columns) is zero. Build the matrix with the vectors as rows:
| 2 | -3 | α |
| 3 | -1 | 3 |
| 1 | -5 | 7 |
Calculate the determinant of the matrix: det = 2((-1)*7 - (-5)*3) - (-3)(3*7 - 1*3) + α(3*(-5) - (-1)*1). Simplify each term: 1. First term: 2 * (−7 + 15) = 2 * 8 = 16. 2. Second term: 3 * (21 − 3) = 3 * 18 = 54. 3. Third term: α * (−15 + 1) = α * (−14) = −14α. Combine: det = 16 + 54 + (−14α). The vectors are linearly dependent when det = 0: 70 - 14α = 0. Solve for α: 14α = 70. α = 5. Verify α is in the range 5,5: Since the range is exactly [5,5], α = 5 is within this range.
Consider the matrix: \[ \begin{bmatrix} 1 & k \\ 2 & 1 \end{bmatrix}, \] where \(k\) is a positive real number. Which of the following vectors is/are eigenvector(s) of this matrix?