Question:medium
Let \(f(x) = \frac{\sqrt[3]{x^4}}{\sqrt[3]{x^2}},\ x \neq 0\). Then the value of \(f'(27)\) is equal to
Let \(f(x) = \frac{\sqrt[3]{x^4}}{\sqrt[3]{x^2}},\ x \neq 0\). Then the value of \(f'(27)\) is equal to
Show Hint
\(\sqrt[3]{x^m} = x^{m/3}\). Simplify before differentiating.
Updated On: Apr 27, 2026
- \(\frac{1}{9}\)
- \(\frac{2}{9}\)
- \(\frac{1}{3}\)
- \(\frac{4}{9}\)
- \(\frac{5}{9}\)
Show Solution
The Correct Option is B
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