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Let \[ A = \begin{pmatrix} 1 & -1 & 1 2 & 1 & -3 1 & 1 & 1 \end{pmatrix}, \quad 10B = \begin{pmatrix} -5 & 0 & \alpha 4 & 2 & 2 1 & -2 & 3 \end{pmatrix} \] If $ B $ is the inverse of matrix $ A $, then $ \alpha $ is:

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When solving for unknowns in matrix multiplication, remember to compare corresponding elements from both sides of the equation and solve for the unknowns step by step.

Updated On: Apr 22, 2026

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The Correct Option is D

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Let \[ A = \begin{pmatrix} 1 & -1 & 1 2 & 1 & -3 1 & 1 & 1 \end{pmatrix}, \quad 10B = \begin{pmatrix} -5 & 0 & \alpha 4 & 2 & 2 1 & -2 & 3 \end{pmatrix} \] If \( B \) is the inverse of matrix \( A \), then \( \alpha \) is:

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The Correct Option is D

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Questions Asked in MET exam