Question:medium

Let \(A\) be the largest positive integer that divides all the numbers of form \(3^k+4^k+5^k\), and \(B\) be the largest positive integer that divides all the numbers of the form \(4^k+3(4^k)+4^{k+2}\), where k is any positive integer. Then \((A+B)\) equals

Updated On: Jan 15, 2026
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Solution and Explanation

Step 1: Evaluating \( 3^k + 4^k + 5^k \)

Calculate the expression for various \( k \) values:

  • For \( k = 1 \): \( 3^1 + 4^1 + 5^1 = 3 + 4 + 5 = 12 \)
  • For \( k = 2 \): \( 3^2 + 4^2 + 5^2 = 9 + 16 + 25 = 50 \)
  • For \( k = 3 \): \( 3^3 + 4^3 + 5^3 = 27 + 64 + 125 = 216 \)

Determine the Highest Common Factor (HCF) of these results: \[ \gcd(12, 50, 216) = 2 \] Thus, \( A = 2 \)

Step 2: Evaluating \( 4^k + 3(4^k) + 4^{k+2} \)

Simplify the expression: \[ 4^k + 3(4^k) + 4^{k+2} = 4^k(1 + 3) + 4^{k+2} = 4^{k+1} + 4^{k+2} = 4^{k+1}(1 + 4) = 5 \cdot 4^{k+1} \]

Calculate the expression for various \( k \) values:

  • For \( k = 1 \): \( B = 5 \cdot 4^{2} = 5 \cdot 16 = 80 \)
  • For \( k = 2 \): \( B = 5 \cdot 4^{3} = 5 \cdot 64 = 320 \)
  • For \( k = 3 \): \( B = 5 \cdot 4^{4} = 5 \cdot 256 = 1280 \)

Determine the HCF: \[ \gcd(80, 320, 1280) = 80 \] Thus, \( B = 80 \)

Final Step: Sum of A and B

\[ A + B = 2 + 80 = \boxed{82} \]

Answer:

\( \boxed{82} \)

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