Given two equations with variables A, B, and C:
Multiply both equations by 2 to remove fractions:
Subtract Equation 1 from Equation 2:
\[ (2B + A + C) - (2A + B + C) = 14 - 10 \] \[ B - A = 4 \]
This yields:
\[ B = A + 4 \quad \text{(Equation 3)} \]
Substitute Equation 3 into Equation 1:
\[ 2A + (A + 4) + C = 10 \] \[ 3A + C = 6 \quad \text{(Equation 4)} \]
Test with integer values:
The values are:
Sum of A and B: \[ A + B = 1 + 5 = \boxed{6} \]