Let A, B and C be the three points in a uniform electric field $\vec{E}$ as shown. The electric potential is Choose the correct answer from the options given below:
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Think of electric field lines exactly like water flowing down a hill due to gravity. Water flows naturally from high altitude (high potential) to low altitude (low potential). Therefore, the point located furthest upstream against the arrows will always be at the highest potential.
Step 1: Recall the direction rule for potential. Electric field lines always point from high potential toward low potential, so potential rises as you move against the field arrows. Step 2: State the gradient relation. Formally $\vec{E} = -\vec{\nabla}V$, which means moving opposite to $\vec{E}$ increases $V$ and moving along $\vec{E}$ decreases $V$. Step 3: Place the three points along the field. In the standard figure, point B lies furthest upstream (against the field), while A and C lie further downstream along the field direction. Step 4: Compare potentials. Since B is the most upstream point, it sits at the highest potential; points downstream are at progressively lower potential. Step 5: Identify the maximum. The greatest potential therefore occurs at point B. Step 6: Conclude. The potential is maximum at B. \[ \boxed{V \text{ is maximum at point B}} \]
