Question

\[ \int(\sin^6x+\cos^6x+3\sin^2x\cos^2x)\,dx= \]

• A. \(-\dfrac{3}{2}\cos2x+C\)
• B. \(x+C\)
• C. \(\dfrac{3}{2}\sin2x+C\)
• D. \(\dfrac{2}{3}x+C\)

Hint:

Remember: \[ \sin^6x+\cos^6x=1-3\sin^2x\cos^2x \] This identity is very useful in integration problems.

Answer 1

The Correct Option is B