Question:medium

\[ \int \frac{dx}{x\sqrt{x^2+4}}= \]

Show Hint

Whenever radicals like $\sqrt{x^2+a^2}$ appear, try substituting the entire radical as a new variable. It often converts the integral into a standard rational form.
Updated On: May 16, 2026
  • \[ \frac12\log\left| \frac{\sqrt{x^2+4}+2}{\sqrt{x^2+4}-2} \right|+C \]
  • \[ \frac14\log\left| \frac{\sqrt{x^2+4}-2}{\sqrt{x^2+4}+2} \right|+C \]
  • \[ \frac12\log\left| \frac{\sqrt{x^2+4}-2}{\sqrt{x^2+4}+2} \right|+C \]
  • \[ \frac14\log\left| \frac{\sqrt{x^2+4}+2}{\sqrt{x^2+4}-2} \right|+C \]
Show Solution

The Correct Option is B

Solution and Explanation

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