Question:medium
$\int\frac{\cos \theta}{2-\sin^{2}\theta}d \theta=$ ________.
$\int\frac{\cos \theta}{2-\sin^{2}\theta}d \theta=$ ________.
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Recognize $du$ in the numerator to pick your $u$.
Updated On: Jun 24, 2026
- $\frac{1}{2}\log|\frac{\sqrt{2}-\sin \theta}{\sqrt{2}+\sin \theta}|+C$
- $\frac{1}{2}\log|\frac{\sqrt{2}+\sin \theta}{\sqrt{2}-\sin \theta}|+C$
- $\log|\frac{\sqrt{2}+\sin \theta}{\sqrt{2}-\sin \theta}|+C$
- $\frac{1}{\sqrt{2}}\log|\frac{\sqrt{2}+\sin \theta}{\sqrt{2}-\sin \theta}|+C$
- $\frac{1}{2\sqrt{2}}\log|\frac{\sqrt{2}+\sin \theta}{\sqrt{2}-\sin \theta}|+C$
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