Question:medium
$\int \frac{1}{x^2}(x^4 + 1)^{3/4} \, dx$ is equal to:
$\int \frac{1}{x^2}(x^4 + 1)^{3/4} \, dx$ is equal to:
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For integrals like this, "taking out" the highest power of $x$ from the root/fractional power is a standard trick to create the derivative of the inner function outside.
Updated On: May 6, 2026
- \( -\frac{(1 + x^4)^{3/4}}{x} + C \)
- \( -\frac{(1 + x^4)^{1/4}}{2x} + C \)
- \( -\frac{(1 + x^4)^{1/4}}{x} + C \)
- \( -\frac{(1 + x^4)^{1/4}}{x^2} + C \)
- \( -\frac{(1 + x^4)^{1/2}}{x} + C \)
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The Correct Option is C
Solution and Explanation
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