Question

In Young's experiment, the intensity ratio of the maxima and minima in an interference pattern produced by two coherent sources is \(36:1\). The ratio of the amplitudes of the two individual sources will be

• A. \(4:7\)
• B. \(5:7\)
• C. \(7:5\)
• D. \(7:4\)

Hint:

In a medium the wavelength is divided by the refractive index.

Answer 1

The Correct Option is C

Step 1: Formula with the medium:
$\beta = \frac{\lambda D}{nd}$ when the whole setup is in a medium of index n.

Step 2: Substitute:
$\beta = \frac{6.3\times10^{-7}\times1.33}{1.33\times10^{-3}} = 6.3\times10^{-4}$ m (B).

Final Answer:
$6.3\times10^{-4}$ m. \[ \boxed{6.3\times10^{-4}\text{ m}} \]