Question:medium

In Young's double slit experiment, we get 15 fringes per cm on the screen, using light of wavelength 5600 Ã…. For the same setting, how many fringes per cm will be obtained with light of wavelength 7000 Ã…?

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In double-slit experiments, the number of fringes per unit length is inversely proportional to the wavelength.
Updated On: Jan 13, 2026
  • 10
  • 12
  • 15
  • 18
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The Correct Option is B

Solution and Explanation


The number of fringes per unit length, \( N \), is inversely proportional to the wavelength, \( \lambda \). This relationship is expressed as: \[ N \propto \frac{1}{\lambda} \] Consequently, the ratio of fringe counts for two different wavelengths is: \[ \frac{N_1}{N_2} = \frac{\lambda_2}{\lambda_1} \] Given the values: \[ \frac{N_1}{15} = \frac{7000}{5600} \] Solving for \( N_1 \) yields: \[ N_1 = 12 \] Therefore, for the wavelength 7000 Ã…, the number of fringes per cm is 12.
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