The number of fringes per unit length, \( N \), is inversely proportional to the wavelength, \( \lambda \). This relationship is expressed as: \[ N \propto \frac{1}{\lambda} \] Consequently, the ratio of fringe counts for two different wavelengths is: \[ \frac{N_1}{N_2} = \frac{\lambda_2}{\lambda_1} \] Given the values: \[ \frac{N_1}{15} = \frac{7000}{5600} \] Solving for \( N_1 \) yields: \[ N_1 = 12 \] Therefore, for the wavelength 7000 Ã…, the number of fringes per cm is 12.