Question:medium

In Young's double slit experiment, the intensity on screen at a point where path difference is $\frac{\lambda}{4}$ is $\frac{K}{2}$. The intensity at a point when path difference is '$\lambda$' will be}

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Path difference of $\lambda$ corresponds to constructive interference (maximum intensity).
Updated On: May 12, 2026
  • 4 K
  • 2 K
  • K
  • $\frac{K}{4}$
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The Correct Option is C

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