Question:easy

In Young's double slit experiment, for the \(n^{\text{th}}\) dark fringe (\(n = 1,2,3,\ldots\)) the phase difference of the interfering waves in radian will be

Show Hint

Dark fringes occur at path difference (2n - 1) lambda/2, and phase difference is 2 pi/lambda times path difference.
Updated On: Oct 1, 2026
  • \(n\cdot \frac{π}{2}\)
  • \((2n+1)π\)
  • \((2n-1)π\)
  • \((2n-1)\frac{π}{2}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Destructive Interference:
Waves cancel when they are an odd multiple of $\pi$ out of phase.

Step 2: Indexing:
Starting with $n=1$ for the first dark fringe, the odd multiples are $\pi,3\pi,5\pi,\ldots$, written as $(2n-1)\pi$.

Step 3: Answer:
Option (C).

Final Answer:
Option (C). \[ \boxed{\text{(C) } (2n-1)\pi} \]
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