Question

In very high electric field \( E > 10^5 \), 

(A) Asymmetric affect disappears 
(B) Electrophoretic affect disappears 
(C) The ion moves so rapidly that it loses its ionic atmosphere. 
(D) The weak electrolyte is completely ionised at all dilutions. 
 

• A. (A), (B) and (D) only
• B. (A) and (C) only
• C. (A), (B), (C) and (D)
• D. (B), (C) and (D) only

Hint:

In very high electric fields, the ions move rapidly and their ionic atmosphere disappears, leading to complete ionization of weak electrolytes.

Answer 1

The Correct Option is A

Step 1: High Electric Field Effects Analysis. In extremely high electric fields, the behavior of ions and electrolytes undergoes significant alteration. Electrophoresis (ion movement driven by an applied electric field) and asymmetry become negligible due to the ions' very high velocities. Rapid ion movement also results in the loss of their ionic atmosphere. Furthermore, weak electrolytes tend to achieve complete ionization under these intense electric field conditions.

Step 2: Option Analysis. - (A) Asymmetric effect vanishes: This statement is accurate, as ions exhibit symmetrical movement in a high electric field. - (B) Electrophoretic effect vanishes: This statement is also accurate; high electric fields influence ion behavior. - (C) Rapid ion movement leads to loss of ionic atmosphere: This is true; ions can shed their ionic atmosphere in high fields. - (D) Weak electrolyte completely ionizes at all dilutions: This is true; the electric field can induce full dissociation of the electrolyte even at low concentrations.

Step 3: Conclusion. The correct selection is (1) (A), (B), and (D) solely, as all enumerated effects are valid under very high electric field conditions.