\( 8 \, \text{mol} \)
\( 4 \, \text{mol} \)
Reaction:
\( 2H_2 + O_2 \rightarrow 2H_2O \)
The balanced equation indicates a 2:2 mole ratio between \( H_2 \) and \( H_2O \).
From the equation: \( 2 \, \text{mol} \, H_2 \) yields \( 2 \, \text{mol} \, H_2O \).
For 4 moles of \( H_2 \) reacting:
\[ \text{moles of } H_2O = \left( \frac{2 \, \text{mol} \, H_2O}{2 \, \text{mol} \, H_2} \right) \times 4 \, \text{mol} \, H_2 = 4 \, \text{mol} \, H_2O \]
4 moles of water are produced. The answer is \( \boxed{4 \, \text{mol}} \)