Question

In the light reactions of photosynthesis, the sequence of electron flow from the exited P680 (PS II) to P700 (PSI) during non-cyclic photophosphorylation is:

• A. $\text{P680}^* \rightarrow \text{Q}_\text{A} \rightarrow \text{Q}_\text{B} \rightarrow \text{Pheo} \rightarrow \text{Cyt } b_6f \text{ complex} \rightarrow \text{Fd} \rightarrow \text{P700}$
• B. $\text{P680}^* \rightarrow \text{Pheo} \rightarrow \text{Q}_\text{A} \rightarrow \text{Q}_\text{B} \rightarrow \text{Cyt } b_6f \text{ complex} \rightarrow \text{PC} \rightarrow \text{P700}$
• C. $\text{P680}^* \rightarrow \text{Q}_\text{A} \rightarrow \text{Q}_\text{B} \rightarrow \text{Pheo} \rightarrow \text{PC} \rightarrow \text{Cyt } b_6f \text{ complex} \rightarrow \text{Fd} \rightarrow \text{P700}$
• D. $\text{P680}^* \rightarrow \text{A}_0 \rightarrow \text{A}_1 \rightarrow \text{FeS}_\text{x} \rightarrow \text{Fd} \rightarrow \text{Cyt } b_6f \text{ complex} \rightarrow \text{PC} \rightarrow \text{P700}$

Hint:

To remember this sequence, use the abbreviation P-P-Q-Q-C-P-P: $\text{P680}^* \rightarrow$ Pheophytin $\rightarrow$ Q$_A \rightarrow$ Q$_B \rightarrow$ Cyt $b_6f \rightarrow$ Plastocyanin $\rightarrow$ P700.

Answer 1

The Correct Option is B