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In the given figure of circle with centre O, chord AB makes an angle of \(80^\circ\) with the centre. Then \(\angle APB\) is
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In a circle, the angle subtended by a chord at the centre is twice the angle subtended at any point on the remaining part of the circle.
JEECUP - 2024
JEECUP
Updated On:
Jan 15, 2026
\(40^\circ\)
\(100^\circ\)
\(140^\circ\)
\(90^\circ\)
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The Correct Option is
A
Solution and Explanation
The angle \(\angle APB\) on the circle's circumference is half the angle at the center. Therefore, \[ \angle APB = \frac{1}{2} \times \angle AOB = \frac{1}{2} \times 80^\circ = 40^\circ \] The correct answer is thus \(40^\circ\).
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