Question:medium

In the following figure magnitude of the magnetic field at the point p is ______.

Show Hint

Break complex wire shapes into simple segments: straight lines, arcs, and circles. Any straight wire segment that aligns perfectly so it points directly at (or away from) the point of interest contributes exactly zero magnetic field!
Updated On: Jun 19, 2026
  • $\frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{r}$
  • $\frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{2r}$
  • $\frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{4r}$
  • $\frac{\mu_0 I}{4\pi r} - \frac{\mu_0 I}{4r}$
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The total magnetic field at point $P$ is the vector sum of fields due to the straight wire and the circular arc.

Step 2: Formula Application:

For a semi-infinite wire, $B_{wire} = \frac{\mu_0 I}{4\pi r}$.
For a quarter-circle arc (angle $\theta = \pi/2$), $B_{arc} = \frac{\mu_0 I}{4\pi r} \times \theta = \frac{\mu_0 I}{4\pi r} \times \frac{\pi}{2} = \frac{\mu_0 I}{8r}$. (Commonly represented as $1/4$ of a full circle: $\frac{1}{4} \frac{\mu_0 I}{2r}$).

Step 3: Explanation:

Assuming both fields are in the same direction (into the page), $B_{net} = \frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{8r}$. If the arc is a semi-circle, the second term is $\frac{\mu_0 I}{4r}$. Based on the options provided, the geometry corresponds to a semi-infinite wire and a semi-circular arc component.

Step 4: Final Answer:

The magnitude is $\frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{4r}$.
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