Step 1: Understanding the Concept:
The total magnetic field at point $P$ is the vector sum of fields due to the straight wire and the circular arc.
Step 2: Formula Application:
For a semi-infinite wire, $B_{wire} = \frac{\mu_0 I}{4\pi r}$.
For a quarter-circle arc (angle $\theta = \pi/2$), $B_{arc} = \frac{\mu_0 I}{4\pi r} \times \theta = \frac{\mu_0 I}{4\pi r} \times \frac{\pi}{2} = \frac{\mu_0 I}{8r}$. (Commonly represented as $1/4$ of a full circle: $\frac{1}{4} \frac{\mu_0 I}{2r}$).
Step 3: Explanation:
Assuming both fields are in the same direction (into the page), $B_{net} = \frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{8r}$. If the arc is a semi-circle, the second term is $\frac{\mu_0 I}{4r}$. Based on the options provided, the geometry corresponds to a semi-infinite wire and a semi-circular arc component.
Step 4: Final Answer:
The magnitude is $\frac{\mu_0 I}{4\pi r} + \frac{\mu_0 I}{4r}$.