To solve this problem, we need to determine the charge flow when the switch \( S \) is closed in a capacitor network connected to a \( 10 \, V \) battery. Given that it is not possible to have a detailed view of the diagram, let's consider a typical capacitor configuration scenario and solve step-by-step:
Thus, on closing the switch \( S \), a charge of \( 5 \, \mu C \) flows from point \( b \) to point \( a \). This implies after reaching equilibrium, Capacitor(s) configuration reached a new stock where a net 5 microcoulombs worth of charge shifted back towards the earlier configuration.
The correct answer is indeed: 5 \(\mu C\) from \( b \) to \( a \).
This reasoning assumes standard circuit behavior and that capacitors can redistribute charges due to reconnection by switch closing. Such problems usually revolve around charge conservation, series/parallel capacitor rules, and potential differences.
Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 