
To find the slant height of the conical part, we will use the Pythagorean theorem. In the diagram, the height of the cone is 4 cm, and the radius (half the diameter of the base) would be 3 cm.
The slant height \( l \) of a cone can be calculated using the formula:
\(l = \sqrt{r^2 + h^2}\)
Where:
Substitute the values into the formula:
\(l = \sqrt{3^2 + 4^2}\)
\(= \sqrt{9 + 16}\)
\(= \sqrt{25}\)
\(= 5\)
Therefore, the slant height of the conical part is 5 cm.
Thus, the correct answer is 5 cm.
In the adjoining figure, PA and PB are tangents to a circle with centre O such that $\angle P = 90^\circ$. If $AB = 3\sqrt{2}$ cm, then the diameter of the circle is
In the adjoining figure, TS is a tangent to a circle with centre O. The value of $2x^\circ$ is